On the quantity $m^2-p^k$ where $p^k m^2$ is an odd perfect number -- Part II

Jose Arnaldo Bebita Dris, Immanuel Tobias San Diego

Published 2021-09-20, updated 2022-03-02Version 2

Let $p^k m^2$ be an odd perfect number with special prime $p$. Extending previous work of the authors, we prove that the inequality $m < p^k$ follows from $m^2 - p^k = 2^r t$, where $r \geq 2$ and $\gcd(2,t)=1$, under the following hypotheses: (a) $m > t > 2^r$, or (b) $m > 2^r > t$. We also prove that the estimate $m^2 - p^k > 2m$ holds. We can also improve this unconditional estimate to $m^2 - p^k > {m^2}/3$.