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arXiv:1609.06627 [math.PR]AbstractReferencesReviewsResources

How round are the complementary components of planar Brownian motion?

Nina Holden, Serban Nacu, Yuval Peres, Thomas S. Salisbury

Published 2016-09-21Version 1

Consider a Brownian motion $W$ in ${\bf C}$ started from $0$ and run for time 1. Let $A(1),A(2),\dots$ denote the bounded connected components of ${\bf C}-W([0,1])$. Let $R(i)$ (resp. $r(i)$) denote the out-radius (resp. in-radius) of $A(i)$ for $i\in\bf N$. Our main result is that ${\bf E}[\sum_i R(i)^2|\log R(i)|^\theta ]<\infty$ for any $\theta<1$. We also prove that $\sum_i r(i)^2|\log r(i)|=\infty$ almost surely. These results have the interpretation that most of the components $A(i)$ have a rather regular or round shape.

Comments: 28 pages, 11 figures
Categories: math.PR
Subjects: 60D05
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