The Abundancy Index of Divisors of Odd Perfect Numbers

Jose Arnaldo B. Dris

Published 2011-03-05, updated 2012-08-03Version 14

If $N = {q^k}{n^2}$ is an odd perfect number, where $q$ is the Euler prime, then we show that $n < q$ is sufficient for Sorli's conjecture that $k = \nu_{q}(N) = 1$ to hold. We also prove that $q^k < 2/3{n^2}$, and that $I(q^k) < I(n)$, where $I(x)$ is the abundancy index of $x$.