arXiv Analytics

Sign in

arXiv:1107.1510 [math.GN]AbstractReferencesReviewsResources

Problem with almost everywhere equality

Piotr Niemiec

Published 2011-07-07Version 1

A topological space $Y$ is said to have (AEEP) if the following condition is fulfilled. Whenever $(X,\mathfrak{M})$ is a measurable space and $f, g: X \to Y$ are two measurable functions, then the set $\Delta(f,g) = \{x \in X:\ f(x) = g(x)\}$ is a member of $\mathfrak{M}$. It is shown that a metrizable space $Y$ has (AEEP) iff the cardinality of $Y$ is no greater than $2^{\aleph_0}$.

Comments: 4 pages
Journal: Ann. Polon. Math. 104 (2012), 105-108
Categories: math.GN
Subjects: 28A20, 28A05
Related articles: Most relevant | Search more
arXiv:math/0204132 [math.GN] (Published 2002-04-10)
Sequence of dualizations of topological spaces is finite
arXiv:0810.3021 [math.GN] (Published 2008-10-16)
$k^*$-Metrizable Spaces and their Applications
arXiv:1501.01949 [math.GN] (Published 2015-01-08)
$P$-Paracompact and $P$-Metrizable Spaces