{ "id": "math/0312467", "version": "v1", "published": "2003-12-26T17:44:34.000Z", "updated": "2003-12-26T17:44:34.000Z", "title": "Nonintersecting Subspaces Based on Finite Alphabets", "authors": [ "Frederique E. Oggier", "N. J. A. Sloane", "A. R. Calderbank", "Suhas N. Diggavi" ], "comment": "14 pages", "categories": [ "math.CO" ], "abstract": "Two subspaces of a vector space are here called ``nonintersecting'' if they meet only in the zero vector. The following problem arises in the design of noncoherent multiple-antenna communications systems. How many pairwise nonintersecting M_t-dimensional subspaces of an m-dimensional vector space V over a field F can be found, if the generator matrices for the subspaces may contain only symbols from a given finite alphabet A subseteq F? The most important case is when F is the field of complex numbers C; then M_t is the number of antennas. If A = F = GF(q) it is shown that the number of nonintersecting subspaces is at most (q^m-1)/(q^{M_t}-1), and that this bound can be attained if and only if m is divisible by M_t. Furthermore these subspaces remain nonintersecting when ``lifted'' to the complex field. Thus the finite field case is essentially completely solved. In the case when F = C only the case M_t=2 is considered. It is shown that if A is a PSK-configuration, consisting of the 2^r complex roots of unity, the number of nonintersecting planes is at least 2^{r(m-2)} and at most 2^{r(m-1)-1} (the lower bound may in fact be the best that can be achieved).", "revisions": [ { "version": "v1", "updated": "2003-12-26T17:44:34.000Z" } ], "analyses": { "subjects": [ "11T22", "11T71", "51E23", "94A99" ], "keywords": [ "finite alphabet", "nonintersecting subspaces", "noncoherent multiple-antenna communications systems", "m-dimensional vector space", "finite field case" ], "note": { "typesetting": "TeX", "pages": 14, "language": "en", "license": "arXiv", "status": "editable", "adsabs": "2003math.....12467O" } } }