{ "id": "2501.13406", "version": "v1", "published": "2025-01-23T06:08:09.000Z", "updated": "2025-01-23T06:08:09.000Z", "title": "Finite groups admitting a regular tournament $m$-semiregular representation", "authors": [ "Dein Wong", "Songnian Xu", "Chi Zhang", "Jinxing Zhao" ], "categories": [ "math.GR" ], "abstract": "For a positive integer $m$, a finite group $G$ is said to admit a tournament $m$-semiregular representation (TmSR for short) if there exists a tournament $\\Gamma$ such that the automorphism group of $\\Gamma$ is isomorphic to $G$ and acts semiregularly on the vertex set of $\\Gamma$ with $m$ orbits. Clearly, every finite group of even order does not admit a TmSR for any positive integer $m$, and T1SR is the well-known tournament regular representation (TRR for short). In 1986, Godsil \\cite{god} proved, by a probabilistic approach, that the only finite groups of odd order without a TRR are $\\mathbb{Z}_3^2$ and $\\mathbb{Z}_3^3$ . More recently, Du \\cite{du} proved that every finite group of odd order has a TmSR for every $m \\geq 2$. The author of \\cite{du} observed that a finite group of odd order has no regular TmSR when $m$ is an even integer, a group of order $1$ has no regular T3SR, and $\\mathbb{Z}_3^2$ admits a regular T3SR. At the end of \\cite{du}, Du proposed the following problem. \\noindent{\\sf\\it Problem.} \\ \\ {\\it For every odd integer $m\\geq 3$, classify finite groups of odd order which have a regular TmSR.} The motivation of this paper is to give an answer for the above problem. We proved that if $G$ is a finite group with odd order $n>1$, then $G$ admits a regular TmSR for any odd integer $m\\geq 3$.", "revisions": [ { "version": "v1", "updated": "2025-01-23T06:08:09.000Z" } ], "analyses": { "subjects": [ "05C25" ], "keywords": [ "odd order", "semiregular representation", "finite groups admitting", "regular tournament", "regular tmsr" ], "note": { "typesetting": "TeX", "pages": 0, "language": "en", "license": "arXiv", "status": "editable" } } }