{ "id": "2408.09020", "version": "v1", "published": "2024-08-16T21:09:18.000Z", "updated": "2024-08-16T21:09:18.000Z", "title": "On the Edge-Connectivity of the Square of a Graph", "authors": [ "Camino Balbuena", "Peter Dankelmann" ], "categories": [ "math.CO" ], "abstract": "Let $G$ be a connected graph. The edge-connectivity of $G$, denoted by $\\lambda(G)$, is the minimum number of edges whose removal renders $G$ disconnected. Let $\\delta(G)$ be the minimum degree of $G$. It is well-known that $\\lambda(G) \\leq \\delta(G)$, and graphs for which equality holds are said to be maximally edge-connected. The square $G^2$ of $G$ is the graph with the same vertex set as $G$, in which two vertices are adjacent if their distance is not more that $2$. In this paper we present results on the edge-connectivity of the square of a graph. We show that if the minimum degree of a connected graph $G$ of order $n$ is at least $\\lfloor \\frac{n+2}{4}\\rfloor$, then $G^2$ is maximally edge-connected, and this result is best possible. We also give lower bounds on $\\lambda(G^2)$ for the case that $G^2$ is not maximally edge-connected: We prove that $\\lambda(G^2) \\geq \\kappa(G)^2 + \\kappa(G)$, where $\\kappa(G)$ denotes the connectivity of $G$, i.e., the minimum number of vertices whose removal renders $G$ disconnected, and this bound is sharp. We further prove that $\\lambda(G^2) \\geq \\frac{1}{2}\\lambda(G)^{3/2} - \\frac{1}{2} \\lambda(G)$, and we construct an infinite family of graphs to show that the exponent $3/2$ of $\\lambda(G)$ in this bound is best possible.", "revisions": [ { "version": "v1", "updated": "2024-08-16T21:09:18.000Z" } ], "analyses": { "subjects": [ "05C40" ], "keywords": [ "edge-connectivity", "minimum number", "removal renders", "minimum degree", "connected graph" ], "note": { "typesetting": "TeX", "pages": 0, "language": "en", "license": "arXiv", "status": "editable" } } }