{
  "id": "1511.07920",
  "version": "v1",
  "published": "2015-11-24T23:45:24.000Z",
  "updated": "2015-11-24T23:45:24.000Z",
  "title": "The minimum rank problem for circulants",
  "authors": [
    "Louis Deaett",
    "Seth A. Meyer"
  ],
  "comment": "27 pages, 3 figures; to appear in Linear Algebra and its Applications",
  "doi": "10.1016/j.laa.2015.10.033",
  "categories": [
    "math.CO"
  ],
  "abstract": "The minimum rank problem is to determine for a graph $G$ the smallest rank of a Hermitian (or real symmetric) matrix whose off-diagonal zero-nonzero pattern is that of the adjacency matrix of $G$. Here $G$ is taken to be a circulant graph, and only circulant matrices are considered. The resulting graph parameter is termed the minimum circulant rank of the graph. This value is determined for every circulant graph in which a vertex neighborhood forms a consecutive set, and in this case is shown to coincide with the usual minimum rank. Under the additional restriction to positive semidefinite matrices, the resulting parameter is shown to be equal to the smallest number of dimensions in which the graph has an orthogonal representation with a certain symmetry property, and also to the smallest number of terms appearing among a certain family of polynomials determined by the graph. This value is then determined when the number of vertices is prime. The analogous parameter over the reals is also investigated.",
  "revisions": [
    {
      "version": "v1",
      "updated": "2015-11-24T23:45:24.000Z"
    }
  ],
  "analyses": {
    "subjects": [
      "05C50",
      "15A03"
    ],
    "keywords": [
      "minimum rank problem",
      "smallest number",
      "circulant graph",
      "usual minimum rank",
      "minimum circulant rank"
    ],
    "tags": [
      "journal article"
    ],
    "publication": {
      "publisher": "Elsevier"
    },
    "note": {
      "typesetting": "TeX",
      "pages": 27,
      "language": "en",
      "license": "arXiv",
      "status": "editable",
      "adsabs": "2015arXiv151107920D"
    }
  }
}