{ "id": "1211.4570", "version": "v1", "published": "2012-11-17T13:22:42.000Z", "updated": "2012-11-17T13:22:42.000Z", "title": "A congruence modulo $n^3$ involving two consecutive sums of powers and its applications", "authors": [ "Romeo Meštrović" ], "comment": "16 pages; the manuscript contains 7 new Giuga-Agoh's-like conjectures", "categories": [ "math.NT" ], "abstract": "For various positive integers $k$, the sums of $k$th powers of the first $n$ positive integers, $S_k(n+1)=1^k+2^k+...+n^k$, have got to be some of the most popular sums in all of mathematics. In this note we prove that for each $k\\ge 2 $$ 2S_{2k+1}(n)- (2k+1)nS_{2k}(n)\\equiv \\{{array}{ll} 0\\,(\\bmod{\\,n^3}) & {\\rm if}\\,\\,k\\,\\,{\\rm is\\,\\,even\\,\\,or}\\,\\, n\\,\\, {\\rm is\\,\\, odd} & {\\rm or} \\,\\, n\\equiv 0\\,(\\bmod{\\,4}) \\frac{n^3}{2}\\,(\\bmod{\\,n^3}) & {\\rm if}\\,\\,k\\,\\,{\\rm is\\,\\, odd} &,\\,{\\rm and}\\,\\, n\\equiv 2\\,(\\bmod{\\,4}). {array}.$$ The above congruence allows us to state an equivalent formulation of Giuga's conjecture. Moreover, we prove that the first above congruence is satisfied modulo $n^4$ whenever $n\\ge 5$ is a prime number such that $n-1\\nmid 2k-2$. In particular, this congruence arises a conjecture for a prime to be Wolstenholme prime. We also propose several Giuga-Agoh's-like conjectures. Further, we establish two congruences modulo $n^3$ for two binomial type sums involving sums of powers $S_{2i}(n)$ with $i=0,1,...,k$. Furthermore, using the above congruence reduced modulo $n^2$, we obtain an extension of Carlitz-von Staudt result for odd power sums.", "revisions": [ { "version": "v1", "updated": "2012-11-17T13:22:42.000Z" } ], "analyses": { "subjects": [ "05A10", "11A07", "11A51", "11B50", "11B65", "11B68" ], "keywords": [ "congruence modulo", "consecutive sums", "applications", "positive integers", "odd power sums" ], "note": { "typesetting": "TeX", "pages": 16, "language": "en", "license": "arXiv", "status": "editable", "adsabs": "2012arXiv1211.4570M" } } }